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View Full Version : Poll: Roger/Rafa: WHO YA GOT?



shtexas
01-31-2009, 01:37 PM
The women aren't the only ones who get polls around here!

So, who ya got?

shtexas
01-31-2009, 01:46 PM
I was upset PMac was immediately dismissive of Rafa's chances. Rafa puts pressure on Roger like no one else can.

Rafa in 4.

Kirkus
01-31-2009, 01:51 PM
PMac has a 'thing' for Roger. It's hard to see him through the cloud of bias.

I took Rafa in 5, but I hope he beats him in 3.

Togtdyalttai
01-31-2009, 02:19 PM
I just don't know if Rafa can play as hard as he has been after that last match. So I took Roger in 4, although I'd sure like to see Rafa take it.

craighickman
01-31-2009, 02:26 PM
Rafa's on a mission.

elisat
01-31-2009, 02:53 PM
I think (or I hope, not sure) Rafa in 4. The court is not that fast and Rafa should be able to recover on time. Was it Wimby 07 where he played several long matches day in day out and was still able to take Roger to the fifth?

patrick
01-31-2009, 03:04 PM
Roger 7-5,6-4,3-6,6-4

waylandboy-tw
01-31-2009, 05:34 PM
Roger in 4. Rafa has certainly had his number but it's usually been on clay. Roddick menitioned in his presser that Roger sees the ball very well at night. He's of course more rested, and the motivation for number 14 is huge. This is also Rafa's first hardcourt Grand Slam final so it is new territory for him. I'd love to see another 5 set thriller but I think it's over in 4.

TennisAnyone74
01-31-2009, 07:20 PM
I said Rafa in 4. It might just be wishful thinking!

TA

Moose
01-31-2009, 07:30 PM
Thanks for getting a Who Ya Got going, shtexas.


I went Roger in 4. And I'll be so pleased to be proven wrong. Vamos Rafa!

luvs10s
01-31-2009, 07:32 PM
I've said Roger in 4, but I have fingers and toes crossed I'm wrong. Vamos Rafa.

Charlie02123
01-31-2009, 10:48 PM
I think Roger's too strong on hardcourt, and very motivated. Hard court is not Nadal's best surface, and he's a little tired.

I don't think it'll be that competitive. Roger in straights.

JTContinental
02-01-2009, 01:43 AM
Roger in straights.